90 Probability Rules (2 of 3)

Example

When Can We Add Probabilities?

Compare these two questions. What do the solutions have in common?

• Question 1: A person with blood type A can receive blood from individuals with type A or O blood. What is the probability that a randomly selected person from the United States can donate blood to someone with type A blood?

• Answer: P(donate to A) = P(blood type A or blood type O) = 0.45 + 0.41 = 0.86. There is an 86% chance that a randomly selected person in the United States can donate blood to someone with type A blood.

• Question 2: What is the probability that a randomly chosen boreal owl nest will either be empty or contain only 1 egg?

• Answer: P(no eggs or 1 egg) = P(no egg) + P(1 egg) = 0.2 + 0.1 = 0.3. There is a 30% chance that a randomly selected boreal owl nest will be empty or contain only one egg.

What do these solutions have in common?

In each case, we have two events and we want to find the probability that either event A or event B occurs. In each case, we added the probabilities. This works because the events have no outcomes in common. When two events have no outcomes in common, they are disjoint.

The events “type A blood” and “type O blood” are disjoint. These events cannot both happen at the same time for a single person. A person cannot have both type A blood and type O blood.

The events “no eggs” and “1 egg” are disjoint. These outcomes cannot both happen at the same time for a single nest. A nest cannot contain no eggs and at the same time contain 1 egg.

If two events are disjoint, then we can add their individual probabilities. We write this fact as a rule:

P(A or B) = P(A) + P(B)

Example

When Can We NOT Add Probabilities?

• Question: What is the probability that a randomly selected student is either a Health Science major or a female?

• Answer: There are 644 Health Science majors and 6,198 females, but 421 students are counted twice because they are both Health Science majors and female. We must subtract these students before calculating the relative frequency:
• [latex]P(\mathrm{Health\; Science\; or\; female})=\frac{644+6,198-421}{12,000}=\frac{6,421}{12,000}\approx 0.54[/latex]
• Now let’s calculate the individual probabilities and see if the rule works:
• [latex]\text{P}(\mathrm{Health\; Science})+\text{P}(\mathrm{female})=\frac{\text{644}}{\text{12,000}}+\frac{\text{6,198}}{\text{12,000}}\approx \text{0.57}[/latex]
• Main point: P(Health Science or female) ≠ P(Health Science) + P(female). In other words, the addition rule does not work here. Why not? The two events “Health Science” and “female” are not disjoint. The data set contains people who are both in the Health Science program and female.

Example

Do We Ever Subtract Probabilities?

Compare these two questions. What do the solutions have in common?

• Question 1: People with blood type O can donate blood to people with any other blood type. For this reason, people with blood type O are called universal donors. What is the probability that a randomly selected person from the United States is not a universal donor?

• Answer: P(NOT a universal donor) = P(blood type is not type O) = P(blood type A, B, or AB) = 0.41 + 0.10 + 0.04 = 0.55. There is a 55% chance that a randomly selected person in the United States is not a universal donor.

Here is another way we can solve this problem. We can use the idea that all of the probabilities together make up 100% of the possibilities. If we add up all the probabilities in the table, we get 1. We can subtract the probability that someone is type O from 1 to find the probability that the person is not type O:

• P(NOT a universal donor) = P(blood type is not type O) = 1 – P(type O) = 1 – 0.45 = 0.55

• Question 2: What is the probability that a randomly selected boreal owl nest is not empty?

• Answer: P(nest is not empty) = P(at least one egg) = P(1, 2, 3, 4, 5, or 6 eggs) = 0.1 + 0.1 + 0.25 + 0.25 + 0.05 + 0.05 = 0.80. There is an 80% chance that the nest you observe has at least one egg.

Here is another approach:

• P(nest is not empty) = P(at least one egg) = 1 – P(0 eggs) = 1 – 0.2 = 0.8.

What do these solutions have in common?

In each case, we have an event that can be interpreted as a “not” statement. The probability that a person is not a universal donor means the person is not type O. The probability that a boreal owl nest is empty means the nest does not contain 0 eggs. In each case, the easy way to compute the probability is to use the complement event. The complement of event A is the event composed of outcomes that are “not A.” In our examples, the complement of “type O blood” is the event composed of “blood types A, B, or AB.” The complement of “0 eggs” is the event composed of “1, 2, 3, 4, 5, or 6 eggs.” When two sets of events are complements, their probabilities add to 1.

When one event is the complement of another, then we can use the complement rule:

P(not A) = 1 – P(A)

We can use this rule to find probabilities only when the two events are complements. Two events are complements when their probabilities add to 1.